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#The sum of the squares of the first ten natural numbers is,
#12 + 22 + ... + 102 = 385
#The square of the sum of the first ten natural numbers is,
#(1 + 2 + ... + 10)2 = 552 = 3025
#Hence the difference between the sum of the squares
#of the first ten natural numbers and the square of the sum is
#Find the difference between the sum of the squares of the first
#one hundred natural numbers and the square of the sum.
import PIL, math
import numpy as np
nums = range(1,11)
numsq = range(1,11)
for i in nums:
i = i*i
print nums
print numsq
sum1 = (sum(nums)**2)
sum2 = (sum(numsq))
print "The sum squared is: " + str(sum1)
print "The sum of the squares is: " + str(sum2)
print "The difference is: " + str(abs(sum2-sum1))
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