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# The sum of the squares of the first ten natural numbers is,
# 12 + 22 + ... + 102 = 385
# The square of the sum of the first ten natural numbers is,
# (1 + 2 + ... + 10)2 = 552 = 3025
# Hence the difference between the sum of the squares
# of the first ten natural numbers and the square of the sum is
# Find the difference between the sum of the squares of the first
# one hundred natural numbers and the square of the sum.

import PIL
import math

nums = range(1, 101)
numsq = []

for i in nums:
    numsq.append(i*i)

sum1 = (sum(nums)**2)
sum2 = (sum(numsq))

print("The sum squared is: " + str(sum1))
print("The sum of the squares is: " + str(sum2))

print("The difference is: " + str(abs(sum2-sum1)))