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-rw-r--r--sumsq.py28
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-# The sum of the squares of the first ten natural numbers is,
-# 12 + 22 + ... + 102 = 385
-# The square of the sum of the first ten natural numbers is,
-# (1 + 2 + ... + 10)2 = 552 = 3025
-# Hence the difference between the sum of the squares
-# of the first ten natural numbers and the square of the sum is
-# Find the difference between the sum of the squares of the first
-# one hundred natural numbers and the square of the sum.
-
-import PIL
-import math
-
-nums = range(1, 11)
-numsq = range(1, 11)
-
-for i in nums:
- i = i*i
-
-print(nums)
-print(numsq)
-
-sum1 = (sum(nums)**2)
-sum2 = (sum(numsq))
-
-print("The sum squared is: " + str(sum1))
-print("The sum of the squares is: " + str(sum2))
-
-print("The difference is: " + str(abs(sum2-sum1)))