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authormjfernez <mjfernez@gmail.com>2020-02-04 20:17:47 -0500
committermjfernez <mjfernez@gmail.com>2020-02-04 20:17:47 -0500
commitc1a037eaa8198935dd4bf5f20e8df398f5f0d910 (patch)
treef73a20777f817e654d57178017c55eb627a60731 /sumsq.py
parent6e19bf3ce11c8722e3260c0457f0389193fd9251 (diff)
downloadProject_Euler_Solutions-c1a037eaa8198935dd4bf5f20e8df398f5f0d910.tar.gz
more cleanup, more c examples
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-# The sum of the squares of the first ten natural numbers is,
-# 12 + 22 + ... + 102 = 385
-# The square of the sum of the first ten natural numbers is,
-# (1 + 2 + ... + 10)2 = 552 = 3025
-# Hence the difference between the sum of the squares
-# of the first ten natural numbers and the square of the sum is
-# Find the difference between the sum of the squares of the first
-# one hundred natural numbers and the square of the sum.
-
-import PIL
-import math
-
-nums = range(1, 11)
-numsq = range(1, 11)
-
-for i in nums:
- i = i*i
-
-print(nums)
-print(numsq)
-
-sum1 = (sum(nums)**2)
-sum2 = (sum(numsq))
-
-print("The sum squared is: " + str(sum1))
-print("The sum of the squares is: " + str(sum2))
-
-print("The difference is: " + str(abs(sum2-sum1)))