2 files changed, 67 insertions, 0 deletions
diff --git a/reworking/wordnums b/reworking/wordnums
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index 0000000..98bbf35
--- /dev/null
+++ b/reworking/wordnums
diff --git a/reworking/wordnums.c b/reworking/wordnums.c
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index 0000000..b7c6b3f
--- /dev/null
+++ b/reworking/wordnums.c
@@ -0,0 +1,67 @@
+#include <stdio.h>
+#include <stdlib.h>
+#include <string.h>
+
+// Problem 17 - Number Letter Counts
+// So I found the string approach to be a pain in the ass in C (see Python solution)
+// But then I realized, hey, I just need the lengths, so you don't have to pass the string!
+const char *ones[10] = {"","one", "two", "three", "four",
+    "five", "six", "seven", "eight", "nine"};
+const char *teens[10] = {"ten", "eleven", "twelve", "thirteen", "fourteen", "fifteen", 
+    "sixteen", "seventeen", "eighteen", "nineteen"};
+const char *tens[10] = {"","", "twenty", "thirty", "forty",
+    "fifty", "sixty", "seventy", "eighty", "ninety"};
+const char *nd = "AND";
+
+
+///starting to think recursion is wrong way to go about this...
+int lengthOfName(char *num){
+    char *word; 
+    // minus 1 for null terminator
+    int digits = strlen(num) - 1;
+    int n = atoi(num);
+    if(digits == 1){
+        printf("here");
+        word = (char *) ones[n];
+        printf("%s\n", word);
+        return strlen(word);
+    }
+    if(digits == 2){
+        // if the first digit, ie. the tens column is 1
+        if(num[0] == '1'){
+            word = (char *) teens[n % 10];
+            printf("%s\n", word);
+            return strlen(word);
+        }
+        // assuming the first digit is not one, if the second digit is 0
+        else if(num[1] == '0'){
+            word = (char *) tens[n / 10];
+            printf("%s\n", word);
+            return strlen(word);
+        }
+        else{
+            char o[2];
+            int on;
+            word = (char *) tens[n / 10];
+            printf("%s", word);
+            o[0] = num[1];
+            printf("%s\n", o);
+            on = lengthOfName(o);
+            return (strlen(word) + on);
+        }
+    }
+    return -1;
+}
+
+int main(){
+    // 4 is the max for this example, +1 for null terminator or if user tries to cheat
+    char n[5];
+    int out;
+    printf("Number from 1 to 1000: ");
+    fgets(n, 10, stdin);
+    if(atoi(n) > 1000)
+        return printf("only up to 1000 in this example, sorry :(\n");
+    out = lengthOfName(n);
+    printf("%d Characters... wow you'll hurt your hands typing that!\n", out);
+    return 0;
+}