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+import PIL, math
+
+#Problem 12 Highly divisible triangular number
+#finds the first number with over 500 factors
+
+def countfactors(num):
+	factors = 0
+	### we only need to know about the FIRST HALF of factors,
+	##one factor implies a second
+	root = int(math.ceil(math.sqrt(num)))
+	divs = range(1, root)
+	for d in divs:
+		if(num%d == 0):
+			factors += 2
+			
+	#Correction if the number is a perfect square
+	if (root * root == num):
+		factors-=1
+	return factors
+
+
+####   MAIN #####
+i=1
+k=1
+j = 0
+while(k < 500):
+	j += i
+	k=countfactors(j)
+	print(str(j) + " has " + str(k) + " factors")
+	i += 1
+
+print("Ding! Ding! {} has over 500 factors, wow!".format(j))