Update README. update reworking

2 files changed, 30 insertions, 18 deletions

diff --git a/reworking/wordnums b/reworking/wordnums
index 8510dee..f30a9da 100755
--- a/reworking/wordnums
+++ b/reworking/wordnums
diff --git a/reworking/wordnums.c b/reworking/wordnums.c
index ad57107..5f48400 100644
--- a/reworking/wordnums.c
+++ b/reworking/wordnums.c
@@ -14,17 +14,17 @@ const char *tens[10] = {"","", "twenty", "thirty", "forty",
 const char *nd = "AND";
 
 
-int lengthOfName(char *num){
+int lengthOfName(char *num) {
     char *word; 
     // minus 1 for null terminator
     int digits = strlen(num) - 1;
     int n = atoi(num);
-    if(digits == 1){
+    printf("The num is now %s", num, digits);
+    if(digits == 1) {
         word = (char *) ones[n];
         printf("%s\n", word);
         return strlen(word);
-    }
-    if(digits == 2){
+    } else if(digits == 2) {
         // if the first digit, ie. the tens column is 1
         if(num[0] == '1'){
             word = (char *) teens[n % 10];
@@ -36,31 +36,43 @@ int lengthOfName(char *num){
             word = (char *) tens[n / 10];
             printf("%s\n", word);
             return strlen(word);
-        }
-        else{
-            // since the input to the function expects a null terminator, an extra '\n' is needed
-            
-            /// substring would be a better way to do this
+        } else {
+            // since the input to the function expects a null terminator, 
+            // an extra '\n' is needed
             char o[2];
             int on;
             word = (char *) tens[n / 10];
             printf("%s", word);
-            o[0] = num[1];
-            o[1] = '\n';
+            strncpy(o, &num[1], 2);
+            printf("%s", o);
             on = lengthOfName(o);
-            //return (strlen(word) + lengthOfName(o));
             return (strlen(word) + on);
         }
+    } else if(digits == 3) {
+        printf("HERE\n\n");
+        word = (char *) ones[n / 100];
+        printf("%shundred", word);
+        if(num[1] == '0' && num[2] == '0') {
+            printf("\n");
+            return strlen(word) + strlen("hundred");
+        } else {
+            char t[3];
+            int te;
+            strncpy(t, &num[1], 3);
+            printf("%s", nd);
+            te = lengthOfName(t);
+            // example: the user inputs, num = 121
+            //      one            hundred            AND         twenty one
+            
+            ////this line breaks the program for some reason
+            //return (strlen(word) + strlen("hundred") + strlen(nd) + te);
+        }
     }
-    if(digits == 3){
-        word = (char *) ones[n / 100]
-        int t = lengthOfName(
-    }
-    // error condition
+    // error condition for debugging, i.e. in case I messed up, return something
     return -1;
 }
 
-int main(){
+int main() {
     // 4 is the max for this example, +1 for null terminator or if user tries to cheat
     char n[5];
     int out;