Finally figured out 17 in C

1 files changed, 0 insertions, 86 deletions

diff --git a/reworking/wordnums.c b/reworking/wordnums.c
deleted file mode 100644
index 5f48400..0000000
--- a/reworking/wordnums.c
+++ /dev/null
@@ -1,86 +0,0 @@
-#include <stdio.h>
-#include <stdlib.h>
-#include <string.h>
-
-// Problem 17 - Number Letter Counts
-// So I found the string approach to be a pain in the ass in C (see Python solution)
-// But then I realized, hey, I just need the lengths, so you don't have to pass the string!
-const char *ones[10] = {"","one", "two", "three", "four",
-    "five", "six", "seven", "eight", "nine"};
-const char *teens[10] = {"ten", "eleven", "twelve", "thirteen", "fourteen", "fifteen", 
-    "sixteen", "seventeen", "eighteen", "nineteen"};
-const char *tens[10] = {"","", "twenty", "thirty", "forty",
-    "fifty", "sixty", "seventy", "eighty", "ninety"};
-const char *nd = "AND";
-
-
-int lengthOfName(char *num) {
-    char *word; 
-    // minus 1 for null terminator
-    int digits = strlen(num) - 1;
-    int n = atoi(num);
-    printf("The num is now %s", num, digits);
-    if(digits == 1) {
-        word = (char *) ones[n];
-        printf("%s\n", word);
-        return strlen(word);
-    } else if(digits == 2) {
-        // if the first digit, ie. the tens column is 1
-        if(num[0] == '1'){
-            word = (char *) teens[n % 10];
-            printf("%s\n", word);
-            return strlen(word);
-        }
-        // assuming the first digit is not one, if the second digit is 0
-        else if(num[1] == '0'){
-            word = (char *) tens[n / 10];
-            printf("%s\n", word);
-            return strlen(word);
-        } else {
-            // since the input to the function expects a null terminator, 
-            // an extra '\n' is needed
-            char o[2];
-            int on;
-            word = (char *) tens[n / 10];
-            printf("%s", word);
-            strncpy(o, &num[1], 2);
-            printf("%s", o);
-            on = lengthOfName(o);
-            return (strlen(word) + on);
-        }
-    } else if(digits == 3) {
-        printf("HERE\n\n");
-        word = (char *) ones[n / 100];
-        printf("%shundred", word);
-        if(num[1] == '0' && num[2] == '0') {
-            printf("\n");
-            return strlen(word) + strlen("hundred");
-        } else {
-            char t[3];
-            int te;
-            strncpy(t, &num[1], 3);
-            printf("%s", nd);
-            te = lengthOfName(t);
-            // example: the user inputs, num = 121
-            //      one            hundred            AND         twenty one
-            
-            ////this line breaks the program for some reason
-            //return (strlen(word) + strlen("hundred") + strlen(nd) + te);
-        }
-    }
-    // error condition for debugging, i.e. in case I messed up, return something
-    return -1;
-}
-
-int main() {
-    // 4 is the max for this example, +1 for null terminator or if user tries to cheat
-    char n[5];
-    int out;
-    printf("Number from 1 to 1000: ");
-    fgets(n, 10, stdin);
-    if(atoi(n) > 1000)
-        return printf("only up to 1000 in this example, sorry :(\n");
-    out = lengthOfName(n);
-    printf("%d Characters... wow you'll hurt your hands typing that!\n", out);
-    return 0;
-}