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authormjfernez <mjfernez@gmail.com>2020-02-09 15:16:26 -0500
committermjfernez <mjfernez@gmail.com>2020-02-09 15:16:26 -0500
commit93ea7fe5957b62f18e8fbd17a21696bd7de6332d (patch)
treed90aed60d687bcf195f1150777f37cbe8a149814 /collatz.py
parent125ec5bc3d8bfc224b7d32bcfbbc37b9fb5d441f (diff)
downloadProject_Euler_Solutions-93ea7fe5957b62f18e8fbd17a21696bd7de6332d.tar.gz
Organized everything, update README
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-rw-r--r--collatz.py28
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diff --git a/collatz.py b/collatz.py
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--- a/collatz.py
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-import PIL
-import math
-
-# Problem 14 Longest Collatz sequence
-# Note, a little slow, takes about 15 seconds.
-# There is probably a more efficient solution out there
-chain = []
-biggo = []
-
-
-def collatz(seed):
- chain.append(seed)
- if(seed == 1):
- return 0
- if(seed % 2 == 0):
- seed = seed/2
- else:
- seed = 3*seed + 1
- collatz(seed)
-
-
-for n in range(1, pow(10, 6)):
- collatz(n)
- if(len(chain) > len(biggo)):
- biggo = chain
- chain = []
-print(biggo)
-print("Has " + str(len(biggo)) + " numbers.")