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author | mjfernez <mjfernez@gmail.com> | 2020-02-09 15:16:26 -0500 |
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committer | mjfernez <mjfernez@gmail.com> | 2020-02-09 15:16:26 -0500 |
commit | 93ea7fe5957b62f18e8fbd17a21696bd7de6332d (patch) | |
tree | d90aed60d687bcf195f1150777f37cbe8a149814 /collatz.py | |
parent | 125ec5bc3d8bfc224b7d32bcfbbc37b9fb5d441f (diff) | |
download | Project_Euler_Solutions-93ea7fe5957b62f18e8fbd17a21696bd7de6332d.tar.gz |
Organized everything, update README
Diffstat (limited to 'collatz.py')
-rw-r--r-- | collatz.py | 28 |
1 files changed, 0 insertions, 28 deletions
diff --git a/collatz.py b/collatz.py deleted file mode 100644 index 74d5e1e..0000000 --- a/collatz.py +++ /dev/null @@ -1,28 +0,0 @@ -import PIL -import math - -# Problem 14 Longest Collatz sequence -# Note, a little slow, takes about 15 seconds. -# There is probably a more efficient solution out there -chain = [] -biggo = [] - - -def collatz(seed): - chain.append(seed) - if(seed == 1): - return 0 - if(seed % 2 == 0): - seed = seed/2 - else: - seed = 3*seed + 1 - collatz(seed) - - -for n in range(1, pow(10, 6)): - collatz(n) - if(len(chain) > len(biggo)): - biggo = chain - chain = [] -print(biggo) -print("Has " + str(len(biggo)) + " numbers.") |