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author | mjf <mjf@localhost.localdomain> | 2020-02-04 12:11:30 -0500 |
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committer | mjf <mjf@localhost.localdomain> | 2020-02-04 12:11:30 -0500 |
commit | 6aa02212cd6dfbb492fa1f70b60a4fe3d48892e5 (patch) | |
tree | 1b655714c9709ee8fce333fcb6a6be3f5533b2d3 /collatz.py.orig | |
parent | 8e431d287c0e89041506da4c4da57e3e3d657d72 (diff) | |
download | Project_Euler_Solutions-6aa02212cd6dfbb492fa1f70b60a4fe3d48892e5.tar.gz |
cleanup and added more c examples:
Diffstat (limited to 'collatz.py.orig')
-rw-r--r-- | collatz.py.orig | 24 |
1 files changed, 0 insertions, 24 deletions
diff --git a/collatz.py.orig b/collatz.py.orig deleted file mode 100644 index 404a2ed..0000000 --- a/collatz.py.orig +++ /dev/null @@ -1,24 +0,0 @@ -import PIL, math - -#Problem 14 Longest Collatz sequence -#Note, a little slow, takes about 15 seconds. -#There is probably a more efficient solution out there -chain = [] -biggo = [] - -def collatz(seed): - chain.append(seed) - if(seed == 1): return 0 - if(seed%2 == 0): - seed = seed/2 - else: - seed = 3*seed +1 - collatz(seed) - -for n in range(1,pow(10,6)): - collatz(n) - if(len(chain)>len(biggo)): - biggo = chain - chain = [] -print(biggo) -print("Has " + str(len(biggo)) +" numbers.") |