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authormjf <mjf@localhost.localdomain>2020-02-04 12:11:30 -0500
committermjf <mjf@localhost.localdomain>2020-02-04 12:11:30 -0500
commit6aa02212cd6dfbb492fa1f70b60a4fe3d48892e5 (patch)
tree1b655714c9709ee8fce333fcb6a6be3f5533b2d3 /collatz.py.orig
parent8e431d287c0e89041506da4c4da57e3e3d657d72 (diff)
downloadProject_Euler_Solutions-6aa02212cd6dfbb492fa1f70b60a4fe3d48892e5.tar.gz
cleanup and added more c examples:
Diffstat (limited to 'collatz.py.orig')
-rw-r--r--collatz.py.orig24
1 files changed, 0 insertions, 24 deletions
diff --git a/collatz.py.orig b/collatz.py.orig
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@@ -1,24 +0,0 @@
-import PIL, math
-
-#Problem 14 Longest Collatz sequence
-#Note, a little slow, takes about 15 seconds.
-#There is probably a more efficient solution out there
-chain = []
-biggo = []
-
-def collatz(seed):
- chain.append(seed)
- if(seed == 1): return 0
- if(seed%2 == 0):
- seed = seed/2
- else:
- seed = 3*seed +1
- collatz(seed)
-
-for n in range(1,pow(10,6)):
- collatz(n)
- if(len(chain)>len(biggo)):
- biggo = chain
- chain = []
-print(biggo)
-print("Has " + str(len(biggo)) +" numbers.")