Added sumsq.c. Fixed pyhton solution for the same

3 files changed, 23 insertions, 6 deletions

diff --git a/06-Sum-Square-Difference/sumsq b/06-Sum-Square-Difference/sumsq
new file mode 100755
index 0000000..8f8aa03
--- /dev/null
+++ b/06-Sum-Square-Difference/sumsq
diff --git a/06-Sum-Square-Difference/sumsq.c b/06-Sum-Square-Difference/sumsq.c
new file mode 100644
index 0000000..1de2ebe
--- /dev/null
+++ b/06-Sum-Square-Difference/sumsq.c
@@ -0,0 +1,20 @@
+#include <stdio.h>
+
+// Find the difference between (1+2+3+...+100)^2 and (1^2+2^2+3^2+...+100^2)
+// I used another math trick here:
+// The sum up to a number can be found using Gauss' Trick:
+// 1 + 2 + 3 + ... + 10 -> (1+9) + (2+8) + (3+7) + (4+6) + 10 + 5 -> 5*10 +5
+// In general : (n/2)(n+1)
+
+int main() {
+    long sqsum = 50 * 101;
+    sqsum *=sqsum;
+    printf("The square of the sum is: %lu\n", sqsum);
+    long sumsq = 0;
+    for(long i = 1; i <= 100; i++) {
+        sumsq += i * i;
+    }
+    printf("The sum of the squares is: %lu\n", sumsq);
+    printf("Difference: %lu\n", sqsum - sumsq);
+    return 0;
+}
diff --git a/06-Sum-Square-Difference/sumsq.py b/06-Sum-Square-Difference/sumsq.py
index fdd43e4..6882eb6 100644
--- a/06-Sum-Square-Difference/sumsq.py
+++ b/06-Sum-Square-Difference/sumsq.py
@@ -10,14 +10,11 @@
 import PIL
 import math
 
-nums = range(1, 11)
-numsq = range(1, 11)
+nums = range(1, 101)
+numsq = []
 
 for i in nums:
-    i = i*i
-
-print(nums)
-print(numsq)
+    numsq.append(i*i)
 
 sum1 = (sum(nums)**2)
 sum2 = (sum(numsq))