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authormjfernez <mjfernez@gmail.com>2020-02-09 15:16:26 -0500
committermjfernez <mjfernez@gmail.com>2020-02-09 15:16:26 -0500
commit93ea7fe5957b62f18e8fbd17a21696bd7de6332d (patch)
treed90aed60d687bcf195f1150777f37cbe8a149814 /10-Summation-of-Primes
parent125ec5bc3d8bfc224b7d32bcfbbc37b9fb5d441f (diff)
downloadProject_Euler_Solutions-93ea7fe5957b62f18e8fbd17a21696bd7de6332d.tar.gz
Organized everything, update README
Diffstat (limited to '10-Summation-of-Primes')
-rwxr-xr-x10-Summation-of-Primes/sumofprimesbin0 -> 16904 bytes
-rw-r--r--10-Summation-of-Primes/sumofprimes.c50
-rw-r--r--10-Summation-of-Primes/sumofprimes.py28
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diff --git a/10-Summation-of-Primes/sumofprimes b/10-Summation-of-Primes/sumofprimes
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diff --git a/10-Summation-of-Primes/sumofprimes.c b/10-Summation-of-Primes/sumofprimes.c
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+#include <stdio.h>
+#include <stdlib.h>
+#include <math.h>
+
+// The number to find primes up to
+int n = 2000000;
+
+// The number of primes in the primes array
+int s = 0;
+
+int *listPrimes(int num){
+ int i;
+ int *primes;
+ int *sieve = (int *) malloc(num * sizeof(int));
+ //initialize to all 1s (except 0 and 1 which are not prime)
+ for(i = 2; i < num; i++)
+ sieve[i] = 1;
+ for(i = 2; i < ceil(sqrt(num)); i++){
+ if(sieve[i] == 1){
+ int j = i * i;
+ while(j < num){
+ sieve[j] = 0;
+ j += i;
+ }
+ }
+ }
+
+ //now check which were prime
+ primes = (int *) malloc(sizeof(int));
+ for(i = 2; i < num; i++){
+ if(sieve[i]){
+ primes[s] = i;
+ s++;
+ primes = (int *) realloc (primes, (s + 1) * sizeof(int));
+ }
+ }
+
+ return primes;
+}
+
+int main(){
+ int *p = listPrimes(n);
+ long long sum = 0;
+ int len = s;
+ for(int i = 0; i < s; i++){
+ sum += p[i];
+ }
+ printf("%ld\n", sum);
+ return 0;
+}
diff --git a/10-Summation-of-Primes/sumofprimes.py b/10-Summation-of-Primes/sumofprimes.py
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+import PIL
+import math
+
+# Problem 10 sum of primes
+
+def prime_factors(number):
+ primes = []
+ if (number <= 1):
+ return [1]
+ a = [1] * number
+ a[0] = 0
+ a[1] = 0 # not prime
+ for i in range(2, int(math.ceil(math.sqrt(number)))):
+ if(a[i] == 1):
+ j = i**2 # cross out all the multiples
+ while(j < number):
+ a[j] = False
+ j += i
+
+ for k in range(2, number):
+ # is prime
+ if(a[k] == 1):
+ primes.append(k)
+ return primes
+
+
+out = prime_factors(2000000)
+print(str(sum(out)))