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author | mjfernez <mjfernez@gmail.com> | 2020-02-09 15:16:26 -0500 |
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committer | mjfernez <mjfernez@gmail.com> | 2020-02-09 15:16:26 -0500 |
commit | 93ea7fe5957b62f18e8fbd17a21696bd7de6332d (patch) | |
tree | d90aed60d687bcf195f1150777f37cbe8a149814 /01-Multiples-of-3-and-5/euler1.c | |
parent | 125ec5bc3d8bfc224b7d32bcfbbc37b9fb5d441f (diff) | |
download | Project_Euler_Solutions-93ea7fe5957b62f18e8fbd17a21696bd7de6332d.tar.gz |
Organized everything, update README
Diffstat (limited to '01-Multiples-of-3-and-5/euler1.c')
-rw-r--r-- | 01-Multiples-of-3-and-5/euler1.c | 13 |
1 files changed, 13 insertions, 0 deletions
diff --git a/01-Multiples-of-3-and-5/euler1.c b/01-Multiples-of-3-and-5/euler1.c new file mode 100644 index 0000000..d89956e --- /dev/null +++ b/01-Multiples-of-3-and-5/euler1.c @@ -0,0 +1,13 @@ +#include <stdio.h> +#include <stdlib.h> +//Problem 1: multiples of 3 and 5 +int main(){ + int max = 1000; + int i; double sum; + + for (i=0;i<max; i++) + if(i%3 == 0 || i%5==0) + sum+= (double) i; + + printf("%f\n", sum); +} |