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| author | mjfernez <mjfernez@gmail.com> | 2021-10-12 20:18:28 -0400 |
|---|---|---|
| committer | mjfernez <mjfernez@gmail.com> | 2021-10-12 20:18:28 -0400 |
| commit | 3cf128d6da667d00bb5bb659413ea55a98a02aff (patch) | |
| tree | 12eb90997dfa63d65fe6da714626271272342320 /01-Multiples-of-3-and-5/euler1.c | |
| parent | 009ce017d99a8deb2089438381c273e8f3ea3b67 (diff) | |
| download | Project_Euler_Solutions-master.tar.gz | |
Diffstat (limited to '01-Multiples-of-3-and-5/euler1.c')
| -rw-r--r-- | 01-Multiples-of-3-and-5/euler1.c | 10 |
1 files changed, 5 insertions, 5 deletions
diff --git a/01-Multiples-of-3-and-5/euler1.c b/01-Multiples-of-3-and-5/euler1.c index d89956e..ff24a08 100644 --- a/01-Multiples-of-3-and-5/euler1.c +++ b/01-Multiples-of-3-and-5/euler1.c @@ -3,11 +3,11 @@ //Problem 1: multiples of 3 and 5 int main(){ int max = 1000; - int i; double sum; + int i, sum = 0; - for (i=0;i<max; i++) - if(i%3 == 0 || i%5==0) - sum+= (double) i; + for (i; i<max; i++) + if (!(i%3) || !(i%5)) + sum+=i; - printf("%f\n", sum); + printf("%d\n", sum); } |